The length of a rectangular piece of steel in a bridge is 2 meters less than triple the width. The perimeter of the piece of steel is 44 meters. Find the length of the piece of steel. Find the width of the piece of steel.
This is an algebraic equation. First we have a square the width is X The length is L=3X-2. P (perimeter is 44) Therefore P = 2L+2X = 2(3x-2) + 2x = 6x - 4 + 2x = 8x - 4 44+4=8x x=48/8 x=6
