Answer:
The charge is moving with the velocity of [tex]1.1\times10^{4}\ m/s[/tex].
Explanation:
Given that,
Charge [tex]q =8.4\times10^{-4}\ C[/tex]
Angle = 35°
Magnetic field strength [tex]B=6.7\times10^{-3}\ T[/tex]
Magnetic force [tex]F=3.5\times10^{-2}\ N[/tex]
We need to calculate the velocity.
The Lorentz force exerted by the magnetic field on a moving charge.
The magnetic force is defined as:
[tex]F = qvB\sin\theta[/tex]
[tex]v = \dfrac{F}{qB\sin\theta}[/tex]
Where,
F = Magnetic force
q = charge
B = Magnetic field strength
v = velocity
Put the value into the formula
[tex]v =\dfrac{3.5\times10^{-2}}{8.4\times10^{-4}\times6.7\times10^{-3}\times\sin35^{\circ}}[/tex]
[tex]v =\dfrac{3.5\times10^{-2}}{8.4\times10^{-4}\times6.7\times10^{-3}\times0.57}[/tex]
[tex]v = 10910.36\ m/s[/tex]
[tex]v = 1.1\times10^{4}\ m/s[/tex]
Hence, The charge is moving with the velocity of [tex]1.1\times10^{4}\ m/s[/tex].
Answer:
D. 1.1 x 10^4 m/s
Explanation:
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