A stone is thrown vertically upwards with an initial velocity of 40 ms-1. Find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
To find the maximum height we use the expression: U²=2gh Where u is the initial velocity, g is gravitational field strength h is the maximum height. h=u²/2g h=40²/20 =1600/20 =80m
