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The number of horns in jackalopes follows the rules for incomplete dominance. alleles are h = 2 horns, h = 0 horns. if a jackalope that has 2 horns is crossed with a jackalope that has no horns, how many horns will their offspring have? give the genotype(s) and phenotype(s) for their offspring.

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mathmate
Question is as interesting as the animal jackalope.

We ASSUME that incomplete dominance of the number of horns gives rise to 0,1 or 2 horns, where hh=>0, Hh=>1 ("blend" of 0 and 2), and HH=>2 horns.

So if HH crosses with hh, the genotype of the offspring will be Hh, i.e. phenotype Hh=> 1 horn

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