Answer : The complete question is attached in answer.
The value of K will be = 2 X[tex] 10^{-5} [/tex]
Explanation : We can use the formula as;
∆G = -RT ln K
on rearranging we get, K = [tex]e^({-deltaG/RT})[/tex]
Therefore, we get,
∆G/RT = (26.81 kJ/mol ) / (0.008314 kJ/mol-K) X (298K) = 10.82
So, K = [tex]e^{-10.82}[/tex]
Therefore, K = 2 X [tex] 10^{-5} [/tex]
