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A function f(x) has x-intercepts of –3 and –5. What is the constant term in the function? f(x) = x2 + 8x +

Respuesta :

maovitt
The constant term is 15, because x^2 + 8x+ 15 factors to (x + 3)(x +5). Thus, by the zero rule x = -3 and -5.
abidemiokin

Quadratic equation is an equation that has a leading degree of 2the constant term in the function f(x) = x2 + 8x + is 15

Quadratic functions

This is an equation that has a leading degree of 2

GIven the following x-intercepts

x = -3 and x = -5

The factors are (x+3) and (x+5)

Take the product

f(x) = (x+3)(x+5)

f(x) = x^2 + 3x + 8x + 15

f(x) = x^2 + 8x + 15

Hence the constant term in the function f(x) = x2 + 8x + is 15

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