Answer:
Empirical formula of [tex]C_{6}H_{12}O_{3}[/tex] is [tex]C_{2}H_{4}O[/tex]
Explanation:
In an empirical formula, smallest possible integers are used as coefficient of constituting atoms.
Here, coefficients of C, H and O are 6,12 and 3 respectively.
We can divide all three coefficients by 3 to get smallest possible integers.
Therefore coefficients of C,H and O would be 2,4 and 1 respectively after dividing with 3.
So empirical formula of [tex]C_{6}H_{12}O_{3}[/tex] is [tex]C_{2}H_{4}O[/tex]
