Using it's concept, it is found that there is a 0.1667 = 16.67% probability for the desired outcome of the die toss.
A probability is given by the number of desired outcomes divided by the number of total outcomes.
For the red die, there are 3 numbers greater than 3 out of 6 numbers, hence:
P(A) = 3/6 = 1/2.
For the green die, there are 2 numbers less than 3 out of 6 numbers, hence:
P(B) = 2/6 = 1/3.
The events are independent, hence the probability of both is given by:
P(A and B) = P(A)P(B) = 1/2 x 1/3 = 1/6 = 0.1667.
0.1667 = 16.67% probability that the red die shows a number larger than three and the green die shows a number less than three.
More can be learned about probabilities at https://brainly.com/question/14398287
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