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A toy rocket is launched from a 2.8 m high platform in such a way that its​ height, h​ (in meters), after t seconds is given by the equation h equals negative 4.9 t squared plus 18.9 t plus 2.8. how long will it take for the rocket to hit the​ ground?

Respuesta :

Answer: 3.98 s (approximately 4 s for practical purposes)


Explanation:


1) Equation given:


h(t) = - 4.9 t² + 18.9 t + 2.8


2) The time it will take the rocket fo hit the ground is given doing h (t) = 0


- 4.9 t² + 18.9 t + 2.8 = 0


3) You can solve that equation using the quadratic equation or working the equation to complete squares.


To use the quadratic equation you have a = - 4.9, b = 18.8, and c = 2.8



With that, t = [-18.8 +/- √ ( 18.8² - 4(-4.9)(2.8) ) ] / (2(-4.9) ) = 3.98 s


(I only picked the positive result because the negative does not have physical meaning).

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