Respuesta :

[tex]\bf \stackrel{slope-intercep~form}{y=mx+b}\\\\ -------------------------------\\\\ \stackrel{y}{4}=\stackrel{slope}{\cfrac{2}{5}}\stackrel{x}{(-4)}+b\implies 4-b=\cfrac{2}{5}(-4)\implies \cfrac{4-b}{-4}=\cfrac{2}{5} \\\\\\ \stackrel{y}{4}=\stackrel{slope}{-\cfrac{8}{5}}\stackrel{x}{(1)}+b\implies 4-b=-\cfrac{8}{5}(1)\implies \cfrac{4-b}{1}=-\cfrac{8}{5}[/tex]
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4 = (2/5 × -4) + b

→ 4 = -8/5 + b

→ -b = -8/5 + (-4)

→ b = 8/5 + 4

→ b = 8 + 20 / 5

→ b = 12

Finally, b = 12

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