Answer:
Option 3rd is correct
The equation has no real number solutions because the discriminant is less than 0
Step-by-step explanation:
Discriminant(D)of a quadratic equation [tex]ax^2+bx+c = 0[/tex] is given by:
[tex]D = b^2-4ac[/tex]
- If D = 0 , real zero of multiplicity 2.
- If D < 0, two zeros that are complex
- if D > 0, then two real zeros that are distinct.
As per the statement:
Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation:
[tex]x^2+4x+8=0[/tex]
On comparing the given equation with [tex]ax^2+bx+c = 0[/tex] Â we have;
a = 1, b = 4 and c = 8
then;
[tex]D = (4)^2-4(1)(8) = 16-32 = -16[/tex]
⇒[tex]D = -16 < 0[/tex]
By definition;
Discriminant is less than 0
equation does not have real roots
Therefore, the equation has no real number solutions because the discriminant is less than 0
