Answer:
0, 6
Step-by-step explanation:
To find : y-coordinates of the points that are 5 units away from the point left parenthesis 1 comma 3 right parenthesis that have an x-coordinate of negative 3
Given:
Point left parenthesis 1 comma 3 right parenthesis i.e point [tex]\left (1 ,3 \right )[/tex]
Also, point is 5 units away from the point left parenthesis 1 comma 3 right parenthesis such that it's x - coordinate is negative 3 i.e, - 3
Distance between points [tex]\left ( -3,y \right )\, \,\left (1 ,3 \right )[/tex] is 5 units,
[tex]\sqrt{(1+3)^2+(3-y)^2}=5\\\sqrt{16+9+y^2-6y}=5\\\sqrt{25+y^2-6y}=5\\y^2-6y+25=25\\y^2-6y=0\\y(y-6)=0\\y=0\,,\,6[/tex]
{ as distance between points [tex]\left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right )[/tex] is equal to [tex]\sqrt{\left ( x_2-x_1 \right )^2+\left ( y_2-y_1 \right )^2}[/tex] }
