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PLEASE HELP!!!! WILL GIVE BRAINLIEST FOR BEST ANSWER!! I ONLY HAVE 3 MINUTES TO ANSWER THIS QUESTION!!!!!! The graph below shows the survey results for a group of students who were asked how many honors classes they have taken and how many elective classes: A scatter plot is shown with the title class choices. The x-axis is labeled a number of honors classes and the y-axis is labeled a number of electives. Data points are located at 1 and 8, 3 and 6, 3 and 9, 5 and 3, 6 and 6, 6 and 9, 8 and 6. A line of best fit crosses the y-axis at 9 and passes through the point 6 and 6. How many elective classes would a student likely have taken if he or she has taken 12 honors classes? (4 points)

Respuesta :

1.) Y= one half x + one
2.) 3 because Y= negative one half x +9
hafsaabdulhai

Answer:

3 electives

Step-by-step explanation:

two points on line of best fit are: (6,6) and (0,9)

gradietn of line= (9-6)/(0-6)=-1/2

y-intercept=9

so equation of line of best fit is,

y= -x/2+9

For number of honors classes equal to 12 that is x=12,

y= -12/2 + 9

y=3

Number of electives =3

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