Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{0}{ h},\stackrel{0}{ k})\qquad \qquad radius=\stackrel{4}{ r} \\\\\\ (x-0)^2+(y-0)^2=4^2\implies x^2+y^2=16[/tex]
groseinger

Answer:

x^2 + y^2 = 16

Step-by-step explanation:

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