If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

A)2st
B)2/st
(not correct)C)2s/t
D)t/2s

To solve this problem you must apply the proccedure shown below.
1. You have that the area of a rectangle is 16s^2t and the length is 8st^2, the widht is:
Area=Length x Width
Width=Area/Length
Width=(16s^2)t/8st^2
2. By simplifying and by applying the exponents properties, you obtain:
Width=2s/t
The answer is: C) 2s/t

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If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.A)2stB)2/st(not correct)C)2s/tD)t/2s

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If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

A)2st
B)2/st
(not correct)C)2s/t
D)t/2s