Respuesta :
The correct question is:
What is the probability that 2 girls and 2 boys will be selected?
Solution:
Total number of students = 10
Ways to select a team of 4 students = 10C4 = 210
2 Boys can be selected from 6 boys in ways = 6C2 = 15
2 Girls can be selected from 4 girls in ways = 4C2 = 6
Number of ways to select 2 boys and 2 girls = 15 x 6 = 90
Probability of choosing 2 boys and 2 girls = 90/210 = 3/7
Thus, if 4 team members are selected, the probability of choosing 2 boys and 2 girls will be 3/7
What is the probability that 2 girls and 2 boys will be selected?
Solution:
Total number of students = 10
Ways to select a team of 4 students = 10C4 = 210
2 Boys can be selected from 6 boys in ways = 6C2 = 15
2 Girls can be selected from 4 girls in ways = 4C2 = 6
Number of ways to select 2 boys and 2 girls = 15 x 6 = 90
Probability of choosing 2 boys and 2 girls = 90/210 = 3/7
Thus, if 4 team members are selected, the probability of choosing 2 boys and 2 girls will be 3/7
Answer:3/7
Step-by-step explanation:
Its a bit lengthy(a lot actually:) but...
to solve said problem use;
4C2 to represent the girls and 6C2 to represent the boys. This will be multiplied and then further divided by sample space 10C4(because 6+4=10 and 2+2=4).
Thus your expression will look as such.
4C2 * 6C2
/10C2
Remember for each 4C2, and such, use the combination format.
4!/2!(4-2)! * 6!/2!(6-2)!
/10!/4!(10-4)! .... which will equal 3/7.
Hope it helps anyone who needs it.
