If the atomic radius of a calcium crystal is 180 pm, what is the length of the edge of the unit cell? (the calcium crystal forms

Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
a = 2√2 r
Given: r = 180 pm
Therefore, a = 2√2 180
= 2 x 1.141 x 180
= 410.76 pm

The length of the edge of the Ca unit cell is 410.76 pm.

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onyebuchinnaji onyebuchinnaji · Answer 2 · 2022-03-11T11:07:29+01:00

The edge length of a a unit cell of calcium crystal is 509.12 pm.

Structure of the Calcium crystals

Calcium crystal has a face center cubic (FCC) structure.

Edge length of the unit cell

The edge length of the unit cell for face center cubic (FCC) structure is given in the following formula;

a = 2r√2

where;

a is edge length
r is the radius

a = 2 x 180 x √2

a = 509.12 pm

Thus, the edge length of a a unit cell of calcium crystal is 509.12 pm.

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