Answer:
[tex]\frac{1}{8}[/tex]
Step-by-step explanation:
Given expression is,
[tex](6m^{-1}n^0)^{-3}[/tex]
[tex]=(6m^{-1})^{-3}[/tex] ( [tex]a^0 =1[/tex] )
[tex]=6^{-3} (m^{-1})^{-3}[/tex] ( [tex](ab)^m=a^mb^m[/tex] )
[tex]=6^{-3} m^{-1\times -3}[/tex] ( [tex](a^m)^n=a^{mn}[/tex] )
[tex]=6^{-3} m^3[/tex]
[tex]=\frac{m^3}{6^3}[/tex] ( [tex]a^m=\frac{1}{a^{-m}}[/tex] )
[tex]=\frac{m^3}{216}[/tex]
We have, m = 3
[tex]=\frac{3^3}{216}[/tex]
[tex]=\frac{27}{216}[/tex]
[tex]=\frac{1}{8}[/tex]
