We have two polynomial functions, namely:
[tex]p(x)=x^3+3x^2-3x-1 \\ \\ q(x)=3x+8[/tex]
The first function has a degree of 3 while the second one has it of 1. So we need to find a value that is not a solution of:
[tex]p(x)=q(x)[/tex]
So we need to match this equations like this:
[tex]p(x)=q(x) \\ x^3+3x^2-3x-1=3x+8 \\ x^3+3x^2-6x-9=0 \\ \\ Solving \ for \ x\ using \ calculator: \\ x_{1}=2.05 \\ x_{2}=-1.11 \\ x_{3}=-3.94[/tex]
So the values that are not solutions of the previous equation are all real numbers except:
[tex]x_{1}=2.05 \\ x_{2}=-1.11 \\ x_{3}=-3.94[/tex]
