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rewrite the following expression as a single logarithm with coefficient 1 3log5 uv^2/w^3

Respuesta :

Answer:

[tex]\log \left ( \frac{125u^3v^6}{w^9} \right )[/tex]

Step-by-step explanation:

Logarithm function is the inverse of an exponential function.

Logarithmic function [tex]\log x[/tex] is defined only for [tex]x>0[/tex].

Its range is set of real numbers.

Real numbers consists of both rational and irrational numbers.

Its curve is called logarithmic curve.

Properties of logarithm:

[tex]\log a^b=b\log a\\\log ab=\log a+\log b\\\log \left ( \frac{a}{b} \right )=\log a-\log b[/tex]

To find:[tex]3\log \left ( \frac{5uv^2}{w^3} \right )[/tex]

[tex]3\log \left ( \frac{5uv^2}{w^3} \right )=\log \left ( \frac{5uv^2}{w^3} \right )^3=\log \left ( \frac{125u^3v^6}{w^9} \right )[/tex]

Coefficient of the final term is 1.

Answer:

The answer is D

Step-by-step explanation:

log5 u^3v^6/w^9

I just did it

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