fqjenfiq9946 fqjenfiq9946 05-04-2024 Mathematics contestada Find a solution of the initial-value problem. y' = xy3 25 y(0) = 15 y = incorrect: your answer is incorrect.a) y =e(x²/2)b) y = 5e(x²/2)c) y = 15e(x²/2)d) y = 25e(x²/2)