A 0. 32M solution of phenol, which is a weak monoprotic acid, has app of 5. 22. Place all the steps required to calculate the value of Ka for phenol in the correct order
A. [H3O+] = 10⁵. 22=6. 0310⁻⁴
B. Assume that [phenol] = 0. 32
C. Ka= (6. 0310⁻⁶)²/(0. 32) =1. 1210⁻¹⁰
D. % ionization = (6. 0310⁻6)/(0. 32)100 = 1. 8710⁻3% so the assumption is justified