Consider the cell described below at 295 k: Sn | Sn²⁺ (0.875 m) || Pb²⁺ (0.931 m) | Pb given E⁰Pb²⁺ → Pb = -0.131 v, E⁰Sn²⁺ → Sn = -0.143 v. calculate the cell potential after the reaction has operated long enough for the Sn²⁺ to have changed by 0.349 mol/l.
