Consider a solution that contains 0.025 M Mn2+ and 0.035 M Co2+. If a 0.100 M NaOH solution is added gradually to selectively precipitate one of the cations, at what concentration (in M) of OH– ions will a precipitate begin to form and what is the identity of the precipitate? Ksp(Mn(OH)2) = 1.60 × 10–13 and Ksp(Co(OH)2) = 5.92 × 10–15 Group of answer choices [OH–] = 2.53 × 10–6 M; Precipitate = Mn(OH)2 [OH–] = 4.83 × 10–12 M; Precipitate = Co(OH)2 [OH–] = 4.11 × 10–7 M; Precipitate = Co(OH)2 [OH–] = 1.69 × 10–13 M; Precipitate = Co(OH)2 [OH–] = 6.40 × 10–12 M; Precipitate = Mn(OH)2