Using the thin lens equation, determine the location and size of each image of the
“4”
when it
is at the
10
cm mark, the
20
cm convex lens
(
objective
)
is at the
80
cm mark and the
10
cm
lens
(
eyepiece
)
is placed at the
114
cm mark on the track. How many times larger is the final
image when the eyepiece is at the
116
cm mark? can someone help me do this? we use the formula
(1/
f
)
=
(1/
d
0)
+
(1/
di
)