Verify that the inverse of a square matrix A of order two is given by the following handy formula, if ad-bc = 0. That is to show that AA⁻¹= I.
a) A⁻¹ = (1/det(A)) * adj(A)
b) A⁻¹ = (1/det(A)) * trans(A)
c) A⁻¹ = (1/det(A)) * inv(A)
d) A⁻¹ = (1/det(A)) * A
