A 0. 32M solution of phenol, Which is a weak monoprotic acid, has app of 5. 22. Place all the steps required to calculate the value of Ka for phenol in the correct order
1. [H3O+] = 10⁵. 22=6. 03*10⁻4
2. Assume that [phenol] = 0. 32
3. Ka= (6. 0310⁻6) ²/(0. 32) =1. 1210⁻10
4. % ionization = (6. 0310⁻6) /(0. 32) 100
= 1. 87*10⁻3% so the assumption is justified