In the planning stage, a sample proportion is estimated as pˆp = 63/90 = 0.70. Use this information to compute the minimum sample size n required to estimate p with 99% confidence if the desired margin of error E = 0.14. What happens to n if you decide to estimate p with 95% confidence? (You may find it useful to reference the z table. Round intermediate calculations to at least 4 decimal places and "z" value to 3 decimal places. Round up your answers to the nearest whole number.)
confidence level n 99%, 95%