alphonseyama alphonseyama 01-04-2024 Mathematics contestada H=R\rightarrow R,H={\left(x.y\right)\x,y\epsilon R,\frac{\left(x-3\right)^2}{4}-\frac{\left(y-4\right)^2}{16}=1} H=R\rightarrow R,H={\left(x.y\right)\x,y\epsilon R,\frac{\left(x-3\right)^2}{4}-\frac{\left(y-4\right)^2}{16}=1}