Consider the bit pattern 0xb56a 4000. Fill out the blanks to calculate the decimal equivalent of the pattern if it is treated as a single-precision floating point.
The sign bit is _____.
The exponent in binary is _____.
The exponent in decimal is _____.
The mantissa in binary is _____.
The mantissa in decimal is _____.
A) The sign bit is 0.
The exponent in binary is 1011 0101.
The exponent in decimal is 181.
The mantissa in binary is 0100 0000 0000 0000 0000 000.
The mantissa in decimal is 0. 25.
B) The sign bit is 1.
The exponent in binary is 1011 0101.
The exponent in decimal is -181.
The mantissa in binary is 0100 0000 0000 0000 0000 000.
The mantissa in decimal is 0. 25.
C) The sign bit is 1.
The exponent in binary is 1101 0101.
The exponent in decimal is 181.
The mantissa in binary is 0100 0000 0000 0000 0000 000.
The mantissa in decimal is 0. 25.
D) The sign bit is 0.
The exponent in binary is 1101 0101.
The exponent in decimal is 181.
The mantissa in binary is 0100 0000 0000 0000 0000 000.
The mantissa in decimal is 0. 25.