Suppose that the weight of an newborn fawn is Uniformly distributed between 2 and 3.6 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible.

The mean of this distribution is

The standard deviation is
The probability that fawn will weigh exactly 2.4 kg is P(x = 2.4) =
The probability that a newborn fawn will be weigh between 2.2 and 3.3 is P(2.2 < x < 3.3) =
The probability that a newborn fawn will be weigh more than 2.62 is P(x > 2.62) =
P(x > 2.2 | x < 3.4) =
Find the 87th percentile.