When photon of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TAeV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.70 eV is
TB=(TA−1.50)eV
. If the de-Broglie wavelength of these photoelectrons is
λb=2λA, then
A. The work function of A is 2.25 eV ​
B. The work function of B is 4.20 eV
C. TA=2.00eV
D. TB=2.75eV

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