Ad = vit + 1/2at?
vf? = vi? + 2ad
v = at
We can break this problem into 2 parts:
Distance traveled with acceleration:
Ad = vi(t) + 1/2at?
The rocket starts from rest so disregard the "vi(t)":
Ad = 1/2at?
Plug in the given acceleration and time:
Ad = 1/2(29.4)(5)?
Ad = 367.5 m
Distance traveled after thrust stops:
Find the displacement up to the top of the trajectory using the equation:
vf? = vi? + 2ad, where vf = 0 m/s
Calculate the initial velocity using the
equation v = at:
v = (29.4)(5) = 147 m/s
Use the above equation and plug in the given values:
03 = (147)? + 2(-9.8)d
Solve for d:
0 = 21,609 - 19.6d
19.6d = 21,609
d = 1,102.5 m

Add the two displacement d1+d2=1,470m