Consider a small surface of area A1=0.0002 m^2, which emits diffusely with a total, hemispherical emissive power of E1=50000 W/m^2. A sensor of small surface area A2=0.0003m^2 intercepts a fraction of emission. n2 02 = 30° A2 r2 = 0.5 m 0 = 60° A1 Q5.6 5 Points If A2 is shifted to 0.25m away from A1 while maintaining the same orientation, the rate of radiation intercepted by A2 would be twice of the original. four times of the original. one-half of the original. the same as the original. Save Answer Q5.7 5 Points If A2 is shifted to the top of A1 whiling keeping the same distance with A1, the rate of radiation intercepted by A2 would remain the same. be zero. increase. Q6 3 Points Consider an opaque, diffuse surface for which the spectral absorptivity and irradiation are shown below: 5000 0.8 Yo (Urt. W/M) 9 0.4 o 0 1 2 3 4 5 0 2 4 6 8 10 λ (μm) 1 (um) Q6.1 1 Point Write a numerical expression for the total irradiation onto the surface: (5000)/2+(5000)(10-2) W/m^2 (2)(5000)/2+(10-2)(5000) W/m^2 5000 W/m^2 O None of the above. Q6.2 1 Point Which equation is correct in determining the total hemispherical absorptivity? G is the irradiation found above (Q5.1). O (0.4(50000)(2)/2+0.8(5-2)(5000))/G O (0.4+0.8)/2.0 O (0.4(50000)(2)/2+0.8(10-2)(5000))/G Save Answer Q6.3 1 Point The radiant flux being reflected by the surface is