At least one of the answers above is NOT correct. (1 point) In this problem you will solve the non-homogeneous differential equation y′′+25y=sec2(5x) (1) Let C1​ and C2​ be arbitrary constants. The general solution to the related homogeneous differential equation y′′+25y=0 is the function yh​(x)=C1​y1​(x)+C2​y2​(x)=C1​ +C2​ NOTE: The order in which you enter the answers is important; that is, C1​f(x)+C2​g(x)=C1​g(x)+C2​f(x). (2) The particular solution yp​(x) to the differential equation y′′+25y=sec2(5x) is of the form yp​(x)=y1​(x)u1​(x)+y2​(x)u2​(x) where u1′​(x)= and u2′​(x)= (3) It follows that u1​(x)= and u2​(x)= thus yp​(x)= (4) The most general solution to the non-homogeneous differential equation y′′+25y=sec2(5x) is y=C1​ +C2​ Note: You can earn partial credit on this problem. Your score was recorded. You have attempted this problem 22 times. You recelved a score of 70% for this attempt. Your overall recorded score is 70%. You have unlimited attempts remaining.