Solve the initial value problem: t(dy/dt) + 4y = t³ + t⁹.
a) y(t) = (t³ + t⁹)/4
b) y(t) = (t³)/4 + (t⁹)/4
c) y(t) = (t⁴)/4 + (t¹⁰)/10
d) y(t) = (t⁴)/16 + (t¹⁰)/40