Let g : Rⁿ ↦ f⁰g ! ℝ. Prove that if limx→0 g (x) = 0 then limx→0 g (x) sin(1/x) = 0:
a) g(x) = sin(1/x)
b) g(x) = 1/x
c) g(x) = 0
d) g(x) = x