Given the following two equations and their corresponding enthalpies:
4 PCl₃ (g) → P₄ (s) + 6 Cl₂ (g) ΔH = 2439 kJ
4 PCl₅ (g) → P₄ (s) + 10 Cl₂ (g) ∆H = 3438 kJ
What is the enthalpy change (∆H) in kJ for the following reaction? Enter your answer with no units.
PCl₅ (g) → PCl₃ (g) + Cl₂ (g)
∆H = _____
