Using the Born-Haber cycle, the δh°f of KBr is equal to:
a) δh°f [K (g)] δh°f [Br (g)] - i1 - e(Br) δhlattice
b) δh°f [K (g)] - δh°f [Br (g)] - i1(K) - e(Br) - δhlattice
c) δh°f [K (g)] - δh°f [Br (g)] i1(K) - e(Br) δhlattice
d) δh°f [K (g)] δh°f [Br (g)] i1(K) e(Br) δhlattice