Use Hess's law to calculate the enthalpy change for the reaction: 2WO₃(s) + 3H₂(g) → 2W(s) + 3H₂O(g) from the given data:
2W(s) + 3O₂(g) → 2WO₃(s) ΔH = -1685.4 kJ
2H₂(g) + O₂(g) → 2H₂O(g) ΔH = -477.84 kJ
What is the enthalpy change for the reaction?
a) -1245.56 kJ
b) -1207.24 kJ
c) -1168.92 kJ
d) -1130.60 kJ