A particle of mass 5.0 kg moves under the influence of the force F(x)=(4.0x^2 −13.0x)N. Suppose a frictional force also acts on the particle. If the particle's speed when it starts at x=−9.0 m is 2.0 m/s and when it arrives at x=8.0 m is 8 m/s, how much work is done on it by the fricrional force between x=−9.0 m and x=8.0 m ?