Consider the integral equation: f(t)-33e-12t = 2t- - [*sen(t - u)f(u)du By applying the Laplace transform to both sides of the above equation, it is obtained that the numerator of the function F(s) is of the form (azs²+ a15+ ao) (s² + 1), where F(s) = L {f(t)}, then the value of ao is equal to