For the function f sketched below, solve the initial value problem y" + 2y + y = f(t), y(0)=2, y'(0) = 0 with the Laplace transform. y 1 y = f(t) t 3 -1 Note: For the solution y(t) explicit formulas valid in the intervals [0, 1], [1,2], [2,00) are required. You must use the Laplace transform for the computation
