When only two treatments are involved, ANOVA and the Student's t-test (Chapter 11) result in the same conclusions. Also, for computed test statistics, = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The other group of eight students took the course as a distance course format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each of the two groups. Traditional Lecture Distance 35 47 32 31 37 48 31 30 30 47 38 33 42 41 a-1. Complete the ANOVA table. (Round your SS, MS, and F values to 2 decimal places and p-value and Fcrit to 4 decimal places. ) SS df MS p-value Ferit Source of Variation Treatment Error Total a-2. Use a q = 0. 01 level of significance, find or compute the critical value of F. (Round your answer to 2 decimal places. ) The critical value of Fis b. Using the t-test from Chapter 11, compute t (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places. )