The plant manager has a goal that (on average) no more than two parts will be in the waiting area at any given time. How much faster (service time E[T] in minutes) will the stamping machine have to perform in order to meet this goal? (Hint: to get an E[Lq]=2 parts we can simply use the quadratic equation and solve for utilization, getting rho=0.72, before deriving our new value for μ; once you manipulate λ and the new rho to get the new μ, you can easily solve for E[T]).