The number of meters above the ground, h, of a projectile fired at an initial velocity of 86 meters per seconu and at an initial height of 6.2 meters is given by h(t)= -4.9t2 +86t +6.2 , where t represents the time, in seconds, since the projectile was fired. If the projectile hits its peak height at t= 8.775 seconds, which of the following is closest to its greatest height?

(1) 265 meters

(2) 422 meters

(3) 384 meters

(4) 578 meters