HURRY PLEASE
Q.14
If [tex]y=3x^{2} -9[/tex]
A. y^{-1} =-\sqrt\frac{x+9}{3}[/tex] such that x is greater than or equal to negative nine
B. [tex]y^{-1} =\sqrt\frac{x+9}{3}[/tex] such that x id less than or equal to negative nine
C. [tex]y^{-1} = -\sqrt \frac{x}{3} +9[/tex] such that x is less than or equal to zero
D. [tex]y^{-1} = -\sqrt \frac{x}{3} + 9[/tex] such that x is greater than or equal to zero