A client is paying you $740.50/oz of Pt to weigh out 1000 Pt samples. The contract between you and the client states that the weight of Pt for each sample is defined to be:

(Weight of the sample.) - (The average noise in the measurement.) - 2 x (The standard deviation in the noise of the measurement.)

→If the signal-to-noise of the measurement could be increased to 25000, estimate how much more money would you make on the contract?←

Assume your starting signal to noise is 300. Assume the same signal as in question 2. Assume all the Pt samples will have a similar weight. Both questions 1 and 2 are pasted below for your reference.

Do not use scientific notation. 1 oz. = 28.3595 g Use all figures. Do not use units or dollar signs.



Question 2: If the average noise for the previous question (see below) was 0.506 g, what would the signal-to-noise be? Do not use scientific notation. Signal-to-noise is unitless. Answer: 310.04

Question 1: A sample of Pt is weighed 5 times with the following results:

50.121 g 50.289 g 50.003 g 50.241 g 49.910 g

What is the signal-to-noise ratio? Do not use scientific notation. Signal-to-noise is unitless. Answer: 313.21