Which probabilities do you need in order to
calculate p(getting a on 2 or fewer spins)?
-p(0 successes)
-p(1 success)
-p(2 successes)
-p(3 successes)
-p(4 successes)
-p(5 successes)
answer: a,b, c

part b:
p(getting a on 2 or fewer spins)= answer: 0.79