An approximate solution to an equation is found using this iterative process.
Xₙ₊₁= (Xₙ)³ - 1 / 4 and x₁= -1
a)
(i) Work out the value of x₂
(ii) Work out the value of x₃

b) Work out the solution to 6 decimal places.

An approximate solution to an equation is found using this iterative process Xₙ Xₙ 1 4 and x 1 a i Work out the value of x ii Work out the value of x b Work out class=
Q&A Education